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Q.The electric potential decreases uniformly from 120120 V to 8080 V as one moves on the xx-axis from x=1x = -1 cm to x=+1x = +1 cm. The electric field at the origin must be (JEE Main 2021)

a
2020 V/cm along +x+x
b
2020 V/cm along x-x
c
1010 V/cm along +x+x
d
1010 V/cm along x-x

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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