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Q.The equation of the tangent to the curve y=(logx)2y = (\log x)^2 at x=ex=e is

a
y=2(xe)y = 2(x - e)
b
y=2(ex)y = 2(e - x)
c
y=2x/ey = 2x/e
d
y=2/xy = 2/x

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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