Q.Solve: $\frac{3x}{2} + \frac{5y}{4} = 7$ and $\frac{x}{3} + \frac{2y}{5} = 3$

x=4, y=2

x=2, y=4

x=6, y=1

x=3, y=3

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.Solve: 3x2+5y4=7\frac{3x}{2} + \frac{5y}{4} = 723x​+45y​=7 and x3+2y5=3\frac{x}{3} + \frac{2y}{5} = 33x​+52y​=3