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Q.The equation of the tangent to the curve y2(2ax)=x3y^2(2a - x) = x^3 at the point (a,a)(a, a) is

a
xy+aa=0x - y + a - a = 0
b
x+y=2ax + y = 2a
c
xy=0x - y = 0
d
2x+y=3a2x + y = 3a

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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