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Q.The maximum area of a rectangle inscribed in the circle x2+y2=a2x^2 + y^2 = a^2 is

a
a2a^2
b
2a22a^2
c
2a2\sqrt{2} a^2
d
a2/2a^2/2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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