Q.The electric field in a region is given by $\vec{E} = (Ax + B)\hat{i}$ . The work done by the external agent in slowly moving a charge $q = 2$ C from $(0,0)$ to $(5,0)$ without acceleration is (JEE Main 2022)

10(A + 5B)

10(A + B)

5(A + 5B)

Zero

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The electric field in a region is given by E⃗=(Ax+B)i^\vec{E} = (Ax + B)\hat{i}E=(Ax+B)i^. The work done by the external agent in slowly moving a charge q=2q = 2q=2 C from (0,0)(0,0)(0,0) to (5,0)(5,0)(5,0) without acceleration is (JEE Main 2022)