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Q.The maximum area of the rectangle that can be inscribed in the ellipse x2a2+y2b2=1\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1 is

a
abab
b
2ab2ab
c
4ab4ab
d
πab\pi ab

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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