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Q.The function f(x)={sin2xxx0 2x=0f(x) = \begin{cases} \dfrac{\sin 2x}{x} & x \ne 0 \ 2 & x = 0 \end{cases} is differentiable at x=0x=0

a
True
b
False
c
Only from right
d
Only from left

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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