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Q.sin2x1+cos2xdx\int \dfrac{\sin 2x}{\sqrt{1 + \cos^2 x}} \, dx equals

a
1+cos2x+C\sqrt{1 + \cos^2 x} + C
b
1+cos2x+C-\sqrt{1 + \cos^2 x} + C
c
21+cos2x+C2 \sqrt{1 + \cos^2 x} + C
d
tan1(cosx)+C\tan^{-1}(\cos x) + C

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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