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TET 2024Medium

Q.If 1312+16=a3b2+c6\frac{1}{\sqrt{3}} - \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{6}} = a\sqrt{3} - b\sqrt{2} + c\sqrt{6}, then a+b+c=?a+b+c=?

a
0
b
1
c
11
d
262\sqrt{6}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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