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Q.sec2x(tanx+2)2dx\int \dfrac{\sec^2 x}{(\tan x + 2)^2} \, dx equals

a
1tanx+2+C\dfrac{1}{\tan x + 2} + C
b
tanx+2+C\tan x + 2 + C
c
1tanx+2+C\dfrac{-1}{\tan x + 2} + C
d
secxtanx+C\sec x \tan x + C

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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