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Q.cos2x+cos8x1+2cos6xdx\int \dfrac{\cos 2x + \cos 8x}{1 + 2\cos 6x} \, dx equals

a
16sin6x+C\dfrac{1}{6} \sin 6x + C
b
sin6x+C\sin 6x + C
c
12sin6x+C\dfrac{1}{2} \sin 6x + C
d
cos6x+C\cos 6x + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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