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Q.∫dxx4+x2+1\int \dfrac{dx}{x^4 + x^2 + 1} equals

a
tan⁡−1(x2+1x2)+C\tan^{-1} \left( \dfrac{x^2 + 1}{x \sqrt{2}} \right) + C
b
12tan⁡−1(x2−12x)+C\dfrac{1}{\sqrt{2}} \tan^{-1} \left( \dfrac{x^2 - 1}{\sqrt{2} x} \right) + C
c
12tan⁡−1(x2+12x)+C\dfrac{1}{\sqrt{2}} \tan^{-1} \left( \dfrac{x^2 + 1}{\sqrt{2} x} \right) + C
d
log⁡∣x2+x+1∣+C\log |x^2 + x + 1| + C

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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