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Q.∫cos⁡4x+sin⁡4xsin⁡4x−cos⁡4x dx\int \dfrac{\cos 4x + \sin 4x}{\sin 4x - \cos 4x} \, dx equals

a
14log⁡∣sin⁡4x−cos⁡4x∣+C\dfrac{1}{4} \log|\sin 4x - \cos 4x| + C
b
log⁡∣sin⁡4x−cos⁡4x∣+C\log|\sin 4x - \cos 4x| + C
c
−14log⁡∣sin⁡4x−cos⁡4x∣+C\dfrac{-1}{4} \log|\sin 4x - \cos 4x| + C
d
tan⁡2x+C\tan 2x + C

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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