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Q.sin2xcos2xsin4x+cos4xdx\int \dfrac{\sin^2 x - \cos^2 x}{\sin^4 x + \cos^4 x} \, dx equals

a
tan1(tan2x)+C\tan^{-1} (\tan^2 x) + C
b
tanx+C\tan x + C
c
cotx+C-\cot x + C
d
12tanx+C\dfrac{1}{2} \tan x + C

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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