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Q.∫sin⁡(tan⁡−1x)1+x2 dx\int \dfrac{\sin(\tan^{-1} x)}{1 + x^2} \, dx equals

a
sin⁡(tan⁡−1x)+C\sin(\tan^{-1} x) + C
b
cos⁡(tan⁡−1x)+C\cos(\tan^{-1} x) + C
c
tan⁡−1x+C\tan^{-1} x + C
d
sin⁡x+C\sin x + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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