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Q.sin8xcos8x12sin2xcos2xdx\int \dfrac{\sin^8 x - \cos^8 x}{1 - 2\sin^2 x \cos^2 x} \, dx equals

a
sin2x+C\sin 2x + C
b
sin2x+C-\sin 2x + C
c
12sin2x+C\dfrac{1}{2} \sin 2x + C
d
cos2x+C\cos 2x + C

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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