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Q.cos4x+1cotxtanxdx\int \dfrac{\cos 4x + 1}{\cot x - \tan x} \, dx equals

a
sin4x+C\sin 4x + C
b
14sin4x+C\dfrac{1}{4} \sin 4x + C
c
cos4x+C\cos 4x + C
d
logsin2x+C\log|\sin 2x| + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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