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Q.∫dxex+e−x+2\int \dfrac{dx}{e^x + e^{-x} + 2} equals

a
tan⁡−1(ex)+C\tan^{-1} (e^x) + C
b
12tan⁡−1(ex)+C\dfrac{1}{2} \tan^{-1} (e^x) + C
c
tan⁡−1(ex/2)+C\tan^{-1} (e^{x/2}) + C
d
12tan⁡−1(e2x)+C\dfrac{1}{2} \tan^{-1} (e^{2x}) + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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