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Q.0π/2sin2xsinx+cosxdx\displaystyle \int_{0}^{\pi/2} \dfrac{\sin^2 x}{\sin x + \cos x} \, dx equals

a
π4\dfrac{\pi}{4}
b
π8\dfrac{\pi}{8}
c
π2\dfrac{\pi}{2}
d
12\dfrac{1}{2}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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