Q.The temperature of a conductor is increased from $20^\circ$ C to $120^\circ$ C. If the temperature coefficient of resistance is $0.004^\circ$ C⁻¹, the percentage increase in resistance is

20\%

40\%

60\%

80\%

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The temperature of a conductor is increased from 20∘20^\circ20∘C to 120∘120^\circ120∘C. If the temperature coefficient of resistance is 0.004∘0.004^\circ0.004∘C⁻¹, the percentage increase in resistance is