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Q.0π/2sinxcosx1+cos2xdx\displaystyle \int_{0}^{\pi/2} \dfrac{\sin x \cos x}{1 + \cos^2 x} \, dx equals

a
π8\dfrac{\pi}{8}
b
π4\dfrac{\pi}{4}
c
12log2\dfrac{1}{2} \log 2
d
log2\log 2

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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