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Q.0πlog(1+2cosx)dx\displaystyle \int_{0}^{\pi} \log(1 + 2\cos x) \, dx equals

a
00
b
πlog3\pi \log 3
c
πlog2\pi \log 2
d
π\pi

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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