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Q.∫01tan⁡−1xx dx\displaystyle \int_{0}^{1} \dfrac{\tan^{-1} x}{x} \, dx equals

a
π4\dfrac{\pi}{4}
b
π216\dfrac{\pi^2}{16}
c
π28\dfrac{\pi^2}{8}
d
∞\infty

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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