Home/Question #2813
PracticeMedium

Q.0π/2sin2xcos4xdx\displaystyle \int_{0}^{\pi/2} \sin^2 x \cos^4 x \, dx equals

a
π16\dfrac{\pi}{16}
b
π32\dfrac{\pi}{32}
c
3π32\dfrac{3\pi}{32}
d
5π32\dfrac{5\pi}{32}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here