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PracticeMedium

Q.∫01xm(1−x)n dx\displaystyle \int_{0}^{1} x^{m} (1 - x)^n \, dx equals

a
m!n!(m+n+1)!\dfrac{m! n!}{(m+n+1)!}
b
Γ(m+1)Γ(n+1)Γ(m+n+2)\dfrac{\Gamma(m+1) \Gamma(n+1)}{\Gamma(m+n+2)}
c
m+nmn\dfrac{m+n}{mn}
d
1m+n+1\dfrac{1}{m+n+1}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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