Q.Two identical parallel plate capacitors $A$ and $B$ are connected in series with a battery of voltage $V$ . Capacitor $B$ contains a dielectric slab of dielectric constant $K$ . The potential difference across capacitor $A$ is (JEE Main 2023)

\dfrac{KV}{K+1}

\dfrac{V}{K+1}

\dfrac{KV}{K-1}

KV

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.Two identical parallel plate capacitors AAA and BBB are connected in series with a battery of voltage VVV. Capacitor BBB contains a dielectric slab of dielectric constant KKK. The potential difference across capacitor AAA is (JEE Main 2023)