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Q.∫0π/2sin⁡xsin⁡x+cos⁡x+sin⁡xcos⁡x dx\displaystyle \int_{0}^{\pi/2} \dfrac{\sin x}{\sin x + \cos x + \sin x \cos x} \, dx equals

a
π6\dfrac{\pi}{6}
b
π4\dfrac{\pi}{4}
c
π3\dfrac{\pi}{3}
d
π2\dfrac{\pi}{2}

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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