Home/Question #2823
PracticeMedium

Q.01tan1x1+x2dx\displaystyle \int_{0}^{1} \dfrac{\tan^{-1} x}{1 + x^2} \, dx equals

a
π8\dfrac{\pi}{8}
b
π4\dfrac{\pi}{4}
c
π216\dfrac{\pi^2}{16}
d
π232\dfrac{\pi^2}{32}

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here