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Q.0π/2dx1+tan3x\displaystyle \int_{0}^{\pi/2} \dfrac{dx}{1 + \tan^3 x} equals

a
π/4\pi/4
b
π/2\pi/2
c
π/8\pi/8
d
00

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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