Home/Question #2842
PracticeMedium

Q.0π/2xsinx1+cos2xdx\displaystyle \int_{0}^{\pi/2} \dfrac{x \sin x}{1 + \cos^2 x} \, dx equals

a
π28\dfrac{\pi^2}{8}
b
π24\dfrac{\pi^2}{4}
c
π4\dfrac{\pi}{4}
d
π2\dfrac{\pi}{2}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here