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Q.ππsin2x1+2xdx\displaystyle \int_{-\pi}^{\pi} \dfrac{\sin^2 x}{1 + 2^x} \, dx dx equals

a
π\pi
b
π2\dfrac{\pi}{2}
c
00
d
π/4\pi/4

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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