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Q.0π/2sinxcosxcos2x+sin2xdx\displaystyle \int_{0}^{\pi/2} \dfrac{\sin x \cos x}{\cos^2 x + \sin^2 x} \, dx equals

a
π4\dfrac{\pi}{4}
b
12\dfrac{1}{2}
c
π8\dfrac{\pi}{8}
d
00

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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