Home/Question #2862
PracticeMedium

Q.01log(1+x)1+x2dx\displaystyle \int_{0}^{1} \dfrac{\log(1 + x)}{1 + x^2} \, dx equals

a
π8log2\dfrac{\pi}{8} \log 2
b
π4log2\dfrac{\pi}{4} \log 2
c
log2\log 2
d
π4\dfrac{\pi}{4}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

Unlock Detailed Solution

Register for Free

Already a member? Login here