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Q.0πlog(2+sinx)dx\displaystyle \int_{0}^{\pi} \log(2 + \sin x) \, dx equals

a
ππlog3\pi \pi \log 3
b
πlog2\pi \log 2
c
00
d
2πlog22 \pi \log 2

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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