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Q.0π/2sinxcosxsin4x+cos4xdx\displaystyle \int_{0}^{\pi/2} \dfrac{\sin x \cos x}{\sin^4 x + \cos^4 x} \, dx equals

a
π8\dfrac{\pi}{8}
b
π4\dfrac{\pi}{4}
c
π2\dfrac{\pi}{2}
d
11

Correct Answer: Option B

The correct solution involves applying the fundamental concept to derive the final value step by step...

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