Q.The capacitance of a parallel plate capacitor is $C_0$ . When half of the space between the plates is filled with a dielectric slab of dielectric constant $K$ (slab parallel to plates), the new capacitance becomes (JEE Main 2021)

\dfrac{K C_0}{K+1}

C_0 (1 + K)/2

2 K C_0/(K+1)

K C_0

The correct solution involves applying the fundamental concept to derive the final value step by step...

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Q.The capacitance of a parallel plate capacitor is C0C_0C0​. When half of the space between the plates is filled with a dielectric slab of dielectric constant KKK (slab parallel to plates), the new capacitance becomes (JEE Main 2021)