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Q.0π/2sinx2+cosxdx\displaystyle \int_{0}^{\pi/2} \dfrac{\sin x}{\sqrt{2} + \cos x} \, dx equals

a
log(2+1)\log(\sqrt{2} + 1)
b
2log(2+1)2 \log(\sqrt{2} + 1)
c
1log(21)1 - \log(\sqrt{2} - 1)
d
log(21)\log(\sqrt{2} - 1)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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