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Q.The solution of the differential equation $\dfrac{dy}{dx} + y \tan x = \cos^2 x$ is

a

y \sec x = \dfrac{1}{2} (\sin x + \tan x) + C

b

y \sec x = \dfrac{1}{2} \sin 2x + C

c

y \cos x = \dfrac{1}{2} (\sin x + \tan x) + C

d

y \sin x = \dfrac{1}{2} \cos 2x + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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