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Q.The solution of the differential equation (x2+y2)dx−2xydy=0(x^2 + y^2)dx - 2xy dy = 0 is

a
x2+y2=Cxx^2 + y^2 = C x
b
x2+y2=Cyx^2 + y^2 = C y
c
x2−y2=Cxx^2 - y^2 = C x
d
log⁡∣x2+y2∣=C+2tan⁡−1(y/x)\log|x^2 + y^2| = C + 2 \tan^{-1}(y/x)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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