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Q.The integrating factor of the differential equation dydx+Py=Q\dfrac{dy}{dx} + Py = Qdxdy​+Py=Q where P=1xlog⁡xP = \dfrac{1}{x \log x}P=xlogx1​, Q=1xQ = \dfrac{1}{x}Q=x1​ is

Correct Answer: Option C

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Q.The integrating factor of the differential equation $\dfrac{dy}{dx} + Py = Q$ where $P = \dfrac{1}{x \log x}$ , $Q = \dfrac{1}{x}$ is