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Q.The solution of dydx=1xy+x2y2+1\dfrac{dy}{dx} = \dfrac{1}{xy + x^2 y^2 + 1} is

a
tan⁡−1(xy)=x+C\tan^{-1}(xy) = x + C
b
tan⁡−1(xy)=log⁡x+C\tan^{-1}(xy) = \log x + C
c
tan⁡−1(xy)+x=C\tan^{-1}(xy) + x = C
d
xy=tan⁡(x+C)xy = \tan(x + C)

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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