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Q.The solution of the differential equation xdydx+y=y2x \dfrac{dy}{dx} + y = y^2 is

a
yex=ex+Cye^x = e^x + C
b
log⁡∣y∣=x+C\log|y| = x + C
c
1y=Ce−x\dfrac{1}{y} = Ce^{-x}
d
1y=x+C\dfrac{1}{y} = x + C

Correct Answer: Option C

The correct solution involves applying the fundamental concept to derive the final value step by step...

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