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Q.The solution of dydx=y(x1)x(y1)\dfrac{dy}{dx} = \dfrac{y(x-1)}{x(y-1)} passing through (1,1)(1,1) is

a
logxy=x+y1\log|xy| = x + y - 1
b
logxy=xy+1\log|xy| = x - y + 1
c
xy=ex+yxy = e^{x+y}
d
xy=exyxy = e^{x-y}

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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