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Q.The solution of dydx=yx\dfrac{dy}{dx} = \dfrac{\sqrt{y}}{x} is

a
2y=log⁡x+C2\sqrt{y} = \log x + C
b
4y=log⁡x+C4\sqrt{y} = \log x + C
c
y=log⁡x+C\sqrt{y} = \log x + C
d
y=(log⁡x+C)2y = (\log x + C)^2

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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