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Q.The solution of dydx+y=e−x\dfrac{dy}{dx} + y = e^{-x}, y(0)=0y(0)=0 is

a
y=e−x−exy = e^{-x} - e^x
b
y=e−x(x−1)y = e^{-x}(x - 1)
c
y=e−x(x+1)y = e^{-x}(x + 1)
d
y=xe−xy = x e^{-x}

Correct Answer: Option D

The correct solution involves applying the fundamental concept to derive the final value step by step...

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The solution of \dfrac{dy}{dx} + y = e^{-x}, y(0)=0 is... | ParikshaNiti