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Q.The differential equation of the family of circles with centre at (2,3)(2,3) is

a
(x−2)2+(y−3)2+(x+y−5)dydx=0(x-2)^2 + (y-3)^2 + (x + y - 5) \dfrac{dy}{dx} = 0
b
(x−2)2+(y−3)2+(x+y+5)dydx=0(x-2)^2 + (y-3)^2 + (x + y + 5) \dfrac{dy}{dx} = 0
c
(x+2)2+(y+3)2+(x+y−5)dydx=0(x+2)^2 + (y+3)^2 + (x + y - 5) \dfrac{dy}{dx} = 0
d
(x−2)2+(y−3)2+(x−y−5)dydx=0(x-2)^2 + (y-3)^2 + (x - y - 5) \dfrac{dy}{dx} = 0

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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