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Q.The solution of the differential equation dydx=1+y21+x2\dfrac{dy}{dx} = \dfrac{1 + y^2}{1 + x^2} is

a
tan⁡−1y−tan⁡−1x=C\tan^{-1} y - \tan^{-1} x = C
b
tan⁡−1y+tan⁡−1x=C\tan^{-1} y + \tan^{-1} x = C
c
tan⁡y+tan⁡x=C\tan y + \tan x = C
d
tan⁡y=Ctan⁡x\tan y = C \tan x

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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