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Q.The solution of dydx=ytan⁡x−2sin⁡x\dfrac{dy}{dx} = y \tan x - 2 \sin x is

a
ysec⁡x=2cos⁡x+Cy \sec x = 2 \cos x + C
b
ysec⁡x=cos⁡2x+Cy \sec x = \cos 2x + C
c
ycos⁡x=2sin⁡x+Cy \cos x = 2 \sin x + C
d
ysin⁡x=cos⁡x+Cy \sin x = \cos x + C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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