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Q.The solution of the differential equation dydx=x+y+2x+y−1\dfrac{dy}{dx} = \dfrac{x + y + 2}{x + y - 1} is

a
x+y+tan⁡−1(x+y)=Cx + y + \tan^{-1}(x + y) = C
b
x+y−tan⁡−1(x+y)=Cx + y - \tan^{-1}(x + y) = C
c
tan⁡−1(x+y)=x+C\tan^{-1}(x + y) = x + C
d
x+y=Cx + y = C

Correct Answer: Option A

The correct solution involves applying the fundamental concept to derive the final value step by step...

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